Đáp án+Giải thích các bước giải:
`ab(a-b)(c+1)+bc(b-c)(a+1)+ca(c-a)(b+1)`
`=ab(a-b)(c+1)+bc(b-c)(a+1)-ca(b+1)(a-c+b-b)`
`=ab(a-b)(c+1)+bc(b-c)(a+1)-ca(b+1)[(a-b)+(b-c)]`
`=ab(a-b)(c+1)-bc(b-c)(a+1)-ca(b+1)(a-b)-ca(b+1)(b-c)`
`=[ab(a-b)(c+1)-ca(b+1)(a-b)]+[bc(a+1)(b-c)-ca(b-c)(b+1)]`
`=a(a-b)[b(c+1)-c(b+1)]+c(b-c)[b(a+1)-a(b+1)]`
`=a(a-b)(bc+b-bc-c)+c(b-c)(ab+b-ab-a)`
`=a(a-b)(b-c)+c(b-c)(b-a)`
`=a(a-b)(b-c)-c(b-c)(a-b)`
`=(a-c)(a-b)(b-c)`
ĐỀ LÀ: `ab(a-b)(c+1)+bc(b-c)(a+1)+ca(c-a)(b+1)` NHƯ NÀY BẠN NHÉ!
