Đáp án:
f) \(\left[ \begin{array}{l}
x = 1\\
x = 3
\end{array} \right.\)
Giải thích các bước giải:
\(\begin{array}{l}
a)\left( {x - 3} \right)\left( {2x + 5} \right) = 0\\
\to \left[ \begin{array}{l}
x - 3 = 0\\
2x + 5 = 0
\end{array} \right.\\
\to \left[ \begin{array}{l}
x = 3\\
x = - \dfrac{5}{2}
\end{array} \right.\\
c){\left( {x - 1} \right)^3} = 0\\
\to x - 1 = 0\\
\to x = 1\\
e)\left( {2x - 5 - x - 2} \right)\left( {2x - 5 + x + 2} \right) = 0\\
\to \left( {x - 7} \right)\left( {3x - 3} \right) = 0\\
\to \left[ \begin{array}{l}
x - 7 = 0\\
3x - 3 = 0
\end{array} \right.\\
\to \left[ \begin{array}{l}
x = 7\\
x = 1
\end{array} \right.\\
b)\left( {x - 2} \right)\left( {x + 2} \right) + \left( {x - 2} \right)\left( {3 - 2x} \right) = 0\\
\to \left( {x - 2} \right)\left( {x + 2 + 3 - 2x} \right) = 0\\
\to \left[ \begin{array}{l}
x - 2 = 0\\
- x + 5 = 0
\end{array} \right.\\
\to \left[ \begin{array}{l}
x = 2\\
x = 5
\end{array} \right.\\
d)x\left( {2x - 7} \right) - 2\left( {2x - 7} \right) = 0\\
\to \left( {2x - 7} \right)\left( {x - 2} \right) = 0\\
\to \left[ \begin{array}{l}
x = \dfrac{7}{2}\\
x = 2
\end{array} \right.\\
f)x\left( {x - 1} \right) - 3\left( {x - 1} \right) = 0\\
\to \left( {x - 1} \right)\left( {x - 3} \right) = 0\\
\to \left[ \begin{array}{l}
x = 1\\
x = 3
\end{array} \right.
\end{array}\)