$\dfrac{62}{x+3}-\dfrac{33}{x}=\dfrac{3}{2}$
$\Leftrightarrow \dfrac{62x}{x(x+3)}-\dfrac{33(x+3)}{x(x+3)}=\dfrac{3}{2}$
$\Leftrightarrow \dfrac{62x-33x-99}{x(x+3)}=\dfrac{3}{2}$
$\Leftrightarrow \dfrac{29x-99}{x^2+3x}=\dfrac{3}{2}$
$\Leftrightarrow 3(x^2+3x)=2(29x-99)$
$\Leftrightarrow 3x^2-49x+198=0$