Em tham khảo nha :
\(\begin{array}{l}
1)\\
{n_{KN{O_3}}} = \dfrac{{20}}{{101}} = 0,198mol\\
{C_{{M_{KN{O_3}}}}} = \dfrac{{0,198}}{{0,85}} = 0,233M\\
2)\\
{C_{{M_{KCl}}}} = \dfrac{{0,5}}{{0,75}} = \frac{2}{3}M\\
3)\\
{n_{KN{O_3}}} = 0,5 \times 2 = 1mol\\
{m_{KN{O_3}}} = 1 \times 101 = 101g\\
4)\\
C{\% _{KCl}} = \dfrac{{20}}{{600}} \times 100\% = 3,33\%
\end{array}\)
