$\\$
`b,`
`|x|=17/9`
`->` \(\left[ \begin{array}{l}x=\dfrac{17}{9}\\x=\dfrac{-17}{9}\end{array} \right.\)
Vì `x<0`
`->x=(-17)/9`
Vậy `x=(-17)/9` khi `x<0`
$\\$
`d,`
`(-2)/3+|x-3/2|=4/3`
`->|x-3/2|=4/3 + 2/3`
`->|x-3/2|=2`
`->` \(\left[ \begin{array}{l}x-\dfrac{3}{2}=2\\x-\dfrac{3}{2}=-2\end{array} \right.\) $\\$ `->` \(\left[ \begin{array}{l}x=2+\dfrac{3}{2}\\x=-2+\dfrac{3}{2}\end{array} \right.\) $\\$ `->` \(\left[ \begin{array}{l}x=\dfrac{7}{2}\\x=\dfrac{-1}{2}\end{array} \right.\)
Vậy `x=7/2` hoặc `x=(-1)/2`
