Giải thích các bước giải:
\(\begin{array}{l}
2b)Duong\,thang\,y = 2x - 1\,giao\,voi\,truc\,hoanh\,tai\,M\left( {\dfrac{1}{2};0} \right)\\
Thay\,x = \dfrac{1}{2};y = 0\,vao\,ham\,so\,y = \left( {m - 2} \right)x + 2\\
0 = \left( {m - 2} \right).\dfrac{1}{2} + 2 \Leftrightarrow m - 2 + 4 = 0 \Leftrightarrow m = - 2\\
c)\,Dths\,y = \left( {m - 2} \right)x + 2\,\,\left( {m \ne 2} \right)\,cat\,Ox\,tai\,A\left( {0; - \dfrac{2}{{m - 2}}} \right)\,v\\
cat\,Oy\,tai\,B\left( {0;2} \right)\\
\Rightarrow OA = \dfrac{2}{{\left| {m - 2} \right|}};OB = 2\\
{S_{OAB}} = \dfrac{1}{2}OA.OB = 1 \Leftrightarrow OA.OB = 2\\
\Leftrightarrow \dfrac{2}{{\left| {m - 2} \right|}}.2 = 2 \Leftrightarrow \left| {m - 2} \right| = 2\\
\Leftrightarrow \left[ \begin{array}{l}
m = 4\\
m = 0
\end{array} \right.\left( {tm} \right)
\end{array}\)
