Câu 1:
Muối: $ClNH_3RCOOH$ ($0,1$ mol)
$\to M_{ClNH_3RCOOH}=\dfrac{11,15}{0,1}=111,5$
$\to M_{NH_2RCOOH}=111,5-36,6=75$ (Glyxin)
Tên gọi:
+ Glyxin
+ Axit $\alpha$aminoaxetic
+ Axit 2-aminoetanoic
Câu 2:
Đặt $n_{NaOH}=x(mol)$
Bảo toàn $OH$:
$n_{H_2O}=n_{NaOH}=x(mol)$
BTKL: $3,75+40x=4,85+18x$
$\to x=0,05$ mol
Đặt $n$: số $COOH$ của aminoaxit
$\to n_X=\dfrac{0,05}{n}(mol)$
$\to M_X=\dfrac{3,75n}{0,05}=75n$
$\to n=1; M_X=75$ (Glyxin)
CTCT: $NH_2CH_2COOH$
Câu 3:
Đặt $n_{NaOH}=x(mol)$
Bảo toàn $OH$:
$n_{H_2O}=n_{NaOH}=x(mol)$
BTKL: $15+40x=19,4+18x$
$\to x=0,2$ mol
$\to n_X=0,2(mol)$
$\to M_X=\dfrac{15}{0,2}=75$ (Glyxin)
CTCT: $NH_2CH_2COOH$