1/
$a,PTPƯ:4Al+3O_2\xrightarrow{t^o} 2Al_2O_3$
$b,n_{O_2}=\dfrac{6,72}{22,4}=0,3mol.$
$c,Theo$ $pt:$ $n_{Al}=\dfrac{4}{3}n_{O_2}=0,4mol.$
$⇒a=m_{Al}=0,4.27=10,8g.$
$d,Theo$ $pt:$ $n_{Al_2O_3}=\dfrac{2}{3}n_{O_2}=0,2mol.$
$⇒b=m_{Al_2O_3}=0,2.102=20,4g.$
2/
$a,PTPƯ:Zn+2HCl\xrightarrow{} ZnCl_2+H_2↑$
$b,n_{H_2}=\dfrac{4,48}{22,4}=0,2mol.$
$Theo$ $pt:$ $n_{ZnCl_2}=n_{Zn}=n_{H_2}=0,2mol.$
$⇒m_{ZnCl_2}=0,2.136=27,2g.$
$c,m_{Zn}=0,2.65=13g.$
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