Đáp án:
$\begin{array}{l}
1)\\
{5^5}:{5^3} - 5x = {1^{2010}}.5\\
\Rightarrow {5^2} - 5x = 1.5\\
\Rightarrow 25 - 5x = 5\\
\Rightarrow 5 - x = 5\\
\Rightarrow x = 0\\
Vay\,x = 0\\
2){2^2} + \left( {x - {3^2}} \right) = {5^3} - {4^3}\\
\Rightarrow 4 + x - 9 = 125 - 64\\
\Rightarrow x = 125 - 64 + 9 - 4\\
\Rightarrow x = 66\\
Vay\,x = 66\\
3){5^2}.2\left( {x + {5^2}} \right) = {1^2} + {2^2}\\
\Rightarrow 25.2.\left( {x + 25} \right) = 1 + 4\\
\Rightarrow 50.\left( {x + 25} \right) = 5\\
\Rightarrow x + 25 = \frac{5}{{50}} = \frac{1}{{10}}\\
\Rightarrow x = \frac{1}{{10}} - 25\\
\Rightarrow x = \frac{{1 - 25.10}}{{10}}\\
\Rightarrow x = \frac{{ - 249}}{{10}}\\
Vay\,x = - \frac{{249}}{{10}}\\
B2)\\
1){5^3}:{5^2} + {7^2}{.2017^0}\\
= 5 + 49.1\\
= 5 + 49\\
= 54\\
2){5^2}.42 + 57.\left( {{5^7}:{5^5}} \right) + {3^2} + {4^2}\\
= 25.42 + {57.5^2} + 25\\
= 25.\left( {42 + 57 + 1} \right)\\
= 25.100\\
= 2500\\
B3)\\
1)128 - 3.\left( {5x + 4} \right) = 26\\
\Rightarrow 3.\left( {5x + 4} \right) = 128 - 26\\
\Rightarrow 3.\left( {5x + 4} \right) = 102\\
\Rightarrow 5x + 4 = 34\\
\Rightarrow 5x = 30\\
\Rightarrow x = 6\\
Vay\,x = 6\\
2){2^2}.\left( {x + 4} \right) - {5^2} = {3^6}:{3^3}\\
\Rightarrow 4.\left( {x + 4} \right) - 25 = {3^3}\\
\Rightarrow 4\left( {x + 4} \right) = 27 + 25\\
\Rightarrow 4\left( {x + 4} \right) = 52\\
\Rightarrow x + 4 = 13\\
\Rightarrow x = 9\\
Vay\,x = 9\\
3){\left( {x - 2} \right)^3} + 7 = 15\\
\Rightarrow {\left( {x - 2} \right)^3} = 8\\
\Rightarrow x - 2 = 2\\
\Rightarrow x = 4\\
Vay\,x = 4\\
4){5^x}.2 + {5^x}.3 = 25\\
\Rightarrow {5^x}.5 = 25\\
\Rightarrow {5^{x + 1}} = {5^2}\\
\Rightarrow x + 1 = 2\\
\Rightarrow x = 1\\
Vay\,x = 1
\end{array}$
