Đáp án:
↓↓
Giải thích các bước giải:
Bài 1:
`(3x ^ n + 1 - 2x ^ n) `
`= 4x ^ 2` ` = (x ^ n (3 - 2) + 1)`
`=4x ^ 2 `
`= (x ^ n + 1) ^ `
`=4x ^ 2 `
`= 4x ^{n + 2} + 4x ^ 2`
Bài 2:
`a)`
$ - 2x (x + 1) + (x - 2) (2x - 3) \\= ( - 2x ^ 2 - 2x) + ( 2x ^ 2 - 7x + 6) \\= - 9x + 6$ `b)` $ (2x - 3) (2x + 3) - 4x (x - 1) + 9 \\= 4x ^ 2 + 9 + ( - 4x ^ 2 + 4x) + 9 \\= - 4x + 18$ `c)` $ 9x (3x ^ 2 - 5x) - (3x + 1) (9x ^ 2 - 18x - 1) \\= (27x ^ 3 - 45x ^ 2) - (27 x ^ 3 - 45 x ^ 2 + 6x - 1) \\= - 6x + 1$ `d)` $ 3x ^ n (6x ^ n - 2) - 2x ^ n (9x ^ n - 1) \\= 18x ^{2n} - 6x ^ n - 18x ^{2n} + 2x ^ n \\= - 4x ^ n $ `e)` $ 5 (3x - 4y ^3) + (9 (2x ^ 2 - y ^ 3) - 2 (x ^ 2 - y ^ 3) ) \\= (15x - 20y ^ 3) + ( (18x ^ 2 - 9y ^ 3) + ( - x ^ 2 +2 y ^ 3) ) \\= 17 x ^ 2 - 27 y ^ 3 + 15x$