Đáp án + Giải thích các bước giải:
`a)(1/9)^2005 . 9^2005 - 96^2 : 24^2`
`= (1/9 . 9)^2005 - (96 : 24)^2`
`= 1^2005 - 4^2`
`= 1 - 16`
`= -15`
`b) (45^10 . 5^20)/75^15``= (
`= ((3^2 . 5)^10 . 5^20)/(3 . 5^2)^15`
`= (3^20 . 5^30)/ (3^15 . 5^30)`
`= 3^5`
`= 234`
`c)(5 . 4^15 . 9^9-4 . 3^20 . 8^9)/(5 . 2^9 . 6^19-7 . 2^29 . 27^8)`
`= (5 . (2^2)^15 . (3^2)^9 - 2^2 . 3^20 . (2^3)^9)/(5 . 2^9 . (2.3)^19 - 7 . 2^29 . (3^3)^8)`
`= (5 . 2^30 . 3^18 - 2^2 . 3^20 . 2^27)/(5 . 2^9 . 2^19 . 3^19 - 7 . 2^29 . 3^24)`
`= (5 . 2^30 . 3^18 - 2^29 . 3^20 . 2)/(5 . 2^28 . 3^19 - 7 . 2^29 . 3^24)`
`= (2^29 . 3^18 . (5 . 2 - 3^2))/(2^28 . 3^18 . (5.3 - 7.2))`
`= (2^29 . 3^18 .1)/(2^28 . 3^18 . 1)`
`= 2`
