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ngocngu15
2 năm trước
Bài 1 a) So sánh $3^{125}$ và $4^{93}$ ; A = $\frac{20^10 + 1}{20^10 - 1}$ và B = $\frac{20^10 - 1}{20^10-3}$ b) Chứng tỏ rằng : B = $\frac{1}{2^3}$ + $\frac{1}{3^2}$ + $\frac{1}{4^2}$ + $\frac{1}{5^2}$ + $\frac{1}{6^2}$ + $\frac{1}{7^2}$ + $\frac{1}{8^2}$ < 1...
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