Bài 1.
$cos^2a=1-sin^2a=1-(\dfrac{3}{5})^2=\dfrac{16}{25}$
$\Rightarrow cosa=-\dfrac{4}{5}$ (do $\dfrac{\pi}{2}<a<\pi$)
$tana=\dfrac{sina}{cosa}=-\dfrac{3}{4}$
$tan(a+\dfrac{\pi}{3})=\dfrac{tana+tan\frac{\pi}{3}}{1-tana.tan\frac{\pi}{3}}$
$=\dfrac{-\frac{3}{4}+\sqrt{3}}{1+\frac{3\sqrt{3}}{4}}$
$=\dfrac{48-25\sqrt{3}}{11}$
Bài 2.
$cos2a=1-2sin^2a=1-2.(\dfrac{3}{4})^2$
$=-\dfrac{1}{8}$
Bài 3.
$sinx+cosx=\dfrac{1}{2}$
$\Rightarrow (sinx+cosx)^2=sin^2x+2sinx.cosx+cos^2x$
$=\dfrac{1}{4}$
$sin2x=2sinx.cosx= \dfrac{1}{4}-1=-\dfrac{3}{4}$