Bài `1`:
`a)` `10`+`3(x-2)`=`2(x+3)-5` ⇔ `10+3x-6`=`2x+6-5`
⇔ `3x`-`2x`=`6`-`5`-`10`+`6` ⇔ `x`=`-3`
`b)``2x(x+2)-3(x+2)=0` ⇔ `(x+2)(2x-3)`=`0`
⇔ \(\left[ \begin{array}{l}x+2=0\\2x-3=0\end{array} \right.\)
⇔ \(\left[ \begin{array}{l}2x-3=0\\x=3/2\end{array} \right.\)
Bài `2`:
`a)``2(3x-2)<3(4x-3)+11`⇔`6x-4<12x-9`
⇔ `6x-12x<4-9` ⇔ `-6x<-5`
⇔ `6x -5` ⇔ `x`.`5/6`