Đáp án:x=-4
Giải thích các bước giải:
x#1,x#2,x#3
(x+4)/(x^2-3x+2)+(x+1)/(x^2-4x+3)=(2x+5)/(x^2-4x+3)
(x+4)/(x^2-x-2x+2)+(x+1)/(x^2-x-3x+3)-(2x+5)/(x^2-x-3x+3)=0
(x+4)/[x(x-1)-2(x-1)]+(x+1)/[x(x-1)-3(x-1)]-(2x+5)/[x(x-1)-3(x-1)]=0
[(x-3)(x+4)+(x-2)(x+1)-(x-2)(2x+5)]/[(x-2)(x-1)(x-3)]=0
x^2+4x-3x-12+x^2+x-2x-2-2x^2-x+10=0
-x-4=0
x=-4