$a) \frac{3x(1-x)}{2(x-1)}= \frac{-3x(x-1)}{2(x-1)}=\frac{-3x}{2}$
$b) \frac{6x^{2}y^{2}}{8xy^{5}}= \frac{3x}{4y^{3}}$
$c) \frac{3(x-y)(x-z)^{2}}{6(x-y)(x-z)}=\frac{x-z}{2}$
$d)\frac{x^{2}-16}{4x-x^{2}}=\frac{-(4-x)(4+x)}{x(4-x)}=\frac{-4-x}{x}$
$e)\frac{x^{2}+4x+3}{2x+6}=\frac{x^{2}+x+3x+3}{2x+6}=\frac{(x+1)(x+3)}{2(x+3)}=\frac{x+1}{2}$
$f)\frac{5(x-y)-3(y-x)}{10(x-y)}=\frac{5(x-y)+3(x-y)}{10(x-y)}=\frac{8(x-y)}{10(x-y)}=\frac{4}{5}$
$g)\frac{2ax^{2}-4ax+2a}{5b-5bx^{2}}=\frac{2a(x^{2}-2x+1)}{-5b(x^{2}-1)}=\frac{2a(x-1)^{2}}{-5b(x-1)(x+1)}=\frac{-2a(x-1)}{5b(x+1)}$
Chỗ nào chưa hiểu rõ bạn hỏi lại nhang
