Đáp án:
Baif1
nCO2: 33,6/22,4=1,5(mol)
a)C+O2--->CO2
1,5_1,5___1,5
mC=1,5.12=18g
mCO2=1,5.44=66g
b)S+O2--->SO2
1,5_1,5___1,5
mS=1,5.32=48g
VSO2=1,5.22,4=33,6(l)
c)4P+5O2--->2P2O5
1,2_1,5_______0,6
mP=1,2.31=37,2g
mP2O5=0,6.142=85,2 g
Bai 2
a) 2HgO---->2Hg +O2
b)Phản ứng trên thuộc phản ứng phân huỷ
c) nHgO=21,7/217=0,1(mol)
theo pt: nO2=1/2 nHgO=0,05 mol suy ra VO2=0,05.22,4=1,12 (l)
theo pt :nHg=nHgO=0,1 mol suy ra mHg=0,1.201=20,1 g
Bai 5
a)KCLO3=> KCL + 3/2O2
x 3/2x
CH4+2O2=>CO2+2H2O
0,5 1
2H2+O2=>2H2O
0,25 0,125
nO2=3/2x=0,125+1
=>x=0,75
mKCLO3=0,75.122,5=91,875g
b) n Al= 6,75/27=0,25(mol)
n Zn= 9,75/65= 0,15 (mol)
4Al+2O2t°→2Al2O3 (1')
0,25-->0,125_________(mol)
2Zn+O2t°→2ZnO (2')
0,15->0,075_________(mol)
2KClO3t°→2KCl+3O2(3')
215<-------------------0,075+0,125=0.2(mol)
m KClO3=215.122,5=493 (g)