Giải thích các bước giải:
\(\begin{array}{l}
1.\\
2Na + S \to N{a_2}S\\
N{a_2}S + 2HCl \to 2NaCl + {H_2}S\\
{n_S} = 0,14mol\\
{n_{Na}} = 0,2mol\\
\to {n_{Na}} > {n_S} \to {n_{Na}}dư\\
\to {n_{N{a_2}S}} = {n_S} = 0,14mol\\
\to {n_{{H_2}S}} = {n_{N{a_2}S}} = 0,14mol\\
\to {V_{{H_2}S}} = 0,14 \times 22,4 = 3,136l\\
2.\\
Fe + S \to FeS\\
FeS + 2HCl \to FeC{l_2} + {H_2}S\\
{n_S} = 0,1mol\\
{n_{Fe}} = 0,2mol\\
\to {n_{Fe}} > {n_S} \to {n_{Fe}}dư\\
\to {n_{FeS}} = {n_{{H_2}S}} = {n_S} = 0,1mol\\
\to {V_{{H_2}S}} = 0,1 \times 22,4 = 2,24l\\
3.\\
Zn + S \to ZnS\\
{n_{Zn}} = 0,2mol\\
{n_S} = 0,15mol\\
\to {n_{Zn}} > {n_S} \to {n_{Zn}}dư\\
\to {n_{ZnS}} = {n_S} = 0,15mol\\
\to {m_{ZnS}} = 14,55g\\
\to {n_{Zn(pt)}} = {n_S} = 0,15mol\\
\to {n_{Zn(dư)}} = 0,05mol\\
\to {m_{Zn(dư)}} = 3,25g
\end{array}\)