Đáp án:
\(\begin{array}{l}
(1)C{O_2} + {H_2}O \to {H_2}C{O_3}\\
(2)BaO + {H_2}O \to Ba{(OH)_2}\\
(3)S{O_2} + {H_2}O \to {H_2}S{O_3}\\
(4)S{O_3} + {H_2}O \to {H_2}S{O_4}\\
(5)N{a_2}O + {H_2}O \to 2NaOH\\
(6)BaO + {H_2}S{O_4} \to BaS{O_4} + {H_2}O\\
(7)F{e_2}{O_3} + 3{H_2}S{O_4} \to F{e_2}{(S{O_4})_3} + 3{H_2}O\\
(8)N{a_2}O + {H_2}S{O_4} \to N{a_2}S{O_4} + {H_2}O\\
(9)C{O_2} + Ca{(OH)_2} \to CaC{O_3} + {H_2}O\\
(10)S{O_2} + Ca{(OH)_2} \to CaS{O_3} + {H_2}O\\
(11)S{O_3} + Ca{(OH)_2} \to CaS{O_4} + {H_2}O\\
(12)CO + Ca{(OH)_2} \to CaC{O_3} + {H_2}
\end{array}\)
