`#Sad`
`a)`
`(x+1)^3+(x-2)^3-2x^2(x-1,5) = 3`
`⇔ x^3+3x^2+3x+1+x^3-6x^2+12x-8-2x^3+3x^2 = 3`
`⇔ (x^3+x^3-2x^3)+(-6x^2+3x^2+3x^2)+(3x+12x)+(1-8) = 3`
`⇔ 15x-7 = 3`
`⇔ 15x = 10`
`⇔ x = 2/3`
`\text{Vậy}` `x=2/3`
`\text{→Áp dụng:}`
`+)` `(A+B)^3 = A^3+3A^2B+3AB^2+B^3`
`+)` `(A-B)^3 = A^3-3A^2B+3AB^2-B^3`
`b)`
`(x+2)(x^2-2x+4)(x-2)(x^2+2x+4) = -65`
`⇔ [(x+2)(x^2-2x+4)][(x-2)(x^2+2x+4)] = -65`
`⇔ (x^3+8)(x^3-8) = -65`
`⇔ x^6-8x^3+8x^3-64 = -65`
`⇔ x^6 = -1`
$\text{→Vì}$ `x^6 >= 0`
$\text{Mà}$ `x^6 = -1`
`⇒` $\text{Không có giá trị}$ `x` $\text{nào thỏa mãn đề bài}$
$\text{→Áp dụng:}$
`+)` `A^3+B^3 = (A+B)(A^2-AB+B^2)`
`+)` `A^3-B^3 = (A-B)(A^2+AB+B^2)`
`2)`
`(2n+3)^2-(2n-1)^2`
`= (2n+3-2n+1)(2n+3+2n-1)`
`= 4(4n-2)`
`= 8(2n-1)` `\vdots` `8`
`⇔` `(2n+3)^2-(2n-1)^2` `\vdots` `8` `AA` `n` `in` `ZZ`
`\text{Vậy biểu thức trên chia hết cho}` `8`
`\text{→Áp dụng:}` `A^2-B^2 = (A-B)(A+B)`