$a$)$1440$:[$41$-($2x-5$)]=$2^{4}$.$3$
⇔$1440$:[$41-2x+5$]=$16.3$
⇔$1440$:[$36-2x$]=$48$
⇔$36-2x=1440:48$
⇔$36-2x=30$
⇔$ 2x =36-30$
⇔$2x =6$
⇔$x =3$
Vậy $x=3$
$b$)$5$.[$225$-($x-10$)]-$125=0$
⇔$5$.[$225$-$x+10$]=$125$
⇔$5$.[$235-x$]=$125$
⇔$235 - x = 125 : 5$
⇔$235-x=25$
⇔$x=210$
Vậy $x=210$