Đáp án:
Giải thích các bước giải:
`A = $\frac{1}{3}$ + $\frac{1}{6}$ + $\frac{1}{12}$ + $\frac{1}{24}$ + $\frac{1}{48}$ + $\frac{1}{96}$`
`⇒3A = 1 + $\frac{1}{12}$ + $\frac{1}{4}$ + $\frac{1}{8}$ +$\frac{1}{16}$ + $\frac{1}{32}$`
`⇒3A = 1 + 1 - $\frac{}{2}$ + $\frac{1}{2}$ - $\frac{1}{4}$ + $\frac{1}{4}$ - $\frac{1}{8}$ + $\frac{1}{8}$ - $\frac{1}{6}$ + $\frac{1}{6}$ - $\frac{1}{12}$`
`⇒3A = 1 + 1 - $\frac{1}{32}$`
`⇒3A = 2 - $\frac{1}{32}$`
`⇒A = ( 2 - $\frac{1}{32}$ ) : 3 = $\frac{21}{32}$`
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