Đáp án:
a) 1M
b) 100ml
c) 100g
Giải thích các bước giải:
\(\begin{array}{l}
a)\\
N{a_2}O + {H_2}O \to 2NaOH\\
{n_{N{a_2}O}} = \dfrac{{6,2}}{{62}} = 0,1\,mol\\
{n_{NaOH}} = 2{n_{N{a_2}O}} = 0,2\,mol\\
{C_M}NaOH = \dfrac{{0,2}}{{0,2}} = 1M\\
b)\\
2NaOH + {H_2}S{O_4} \to N{a_2}S{O_4} + 2{H_2}O\\
{n_{{H_2}S{O_4}}} = \dfrac{{0,2}}{2} = 0,1\,mol\\
{V_{{\rm{dd}}{H_2}S{O_4}}} = \dfrac{{0,1}}{1} = 0,1l = 100ml\\
c)\\
NaOH + HCl \to NaCl + {H_2}O\\
{n_{HCl}} = {n_{NaOH}} = 0,2\,mol\\
{m_{{\rm{dd}}HCl}} = \dfrac{{0,2 \times 36,5}}{{7,3\% }} = 100g
\end{array}\)