Giải thích các bước giải:
\(\left\{ \begin{array}{l}
3x + m = y\\
9x + 3\sqrt 3 = {m^2}y
\end{array} \right.\)
a. Vô số nghiệm
\(\begin{array}{l}
\Leftrightarrow \left\{ \begin{array}{l}
\frac{3}{9} = \frac{m}{{3\sqrt 3 }}\\
\frac{1}{{{m^2}}} = \frac{3}{9}
\end{array} \right. \to \left\{ \begin{array}{l}
m = \sqrt 3 \\
\left[ \begin{array}{l}
m = \sqrt 3 \\
m = - \sqrt 3
\end{array} \right.
\end{array} \right.\\
\to m = \sqrt 3
\end{array}\)
b. Vô nghiệm
\(\begin{array}{l}
\Leftrightarrow \left\{ \begin{array}{l}
\frac{3}{9} \ne \frac{m}{{3\sqrt 3 }}\\
\frac{1}{{{m^2}}} = \frac{3}{9}
\end{array} \right. \to \left\{ \begin{array}{l}
m \ne \sqrt 3 \\
\left[ \begin{array}{l}
m = \sqrt 3 \\
m = - \sqrt 3
\end{array} \right.
\end{array} \right.\\
\to m = - \sqrt 3
\end{array}\)
c. Nghiệm duy nhất
\( \Leftrightarrow \frac{1}{{{m^2}}} \ne \frac{3}{9} \Leftrightarrow \left[ \begin{array}{l}
m \ne \sqrt 3 \\
m \ne - \sqrt 3
\end{array} \right.\)
