Đáp án:
C5H12
Giải thích các bước giải:
\[\begin{gathered}
X:\;{{\text{C}}_n}{H_{2n + 2}} \hfill \\
{C_n}{H_{2n + 2}} + (1,5n + 0,5){O_2}\xrightarrow{{}}nC{O_2} + (n + 1){H_2}O \hfill \\
{n_{C{O_2}}} = \frac{{5,6}}{{22,4}} = 0,25{\text{ mol = }}{{\text{n}}_C} \hfill \\
{m_X} = {m_C} + {m_H} \to {m_H} = 3,6 - 0,25.12 = 0,6 \to {n_H} = 0,6{\text{ mol}} \hfill \\
\to {{\text{n}}_{{H_2}O}} = 0,3{\text{ mol}} \hfill \\
\to {{\text{n}}_X} = {n_{{H_2}O}} - {n_{C{O_2}}} = 0,3 - 0,25 = 0,05{\text{ mol}} \hfill \\
\to {\text{n = }}\frac{{{n_{C{O_2}}}}}{{{n_X}}} = \frac{{0,25}}{{0,05}} = 5 \to X:\;{{\text{C}}_5}{H_{12}} \hfill \\
\end{gathered} \]
