Bài 3 : Giải các phương trình sau
1, $\frac{x+2}{X-2}$ - $\frac{6}{x+2}$ = $\frac{x^{2}}{x^{2}-4}$
2, $\frac{x}{x+2}$ - $\frac{3}{x-2}$ = $\frac{x^{2}+8}{x^{2}-4}$
3, $\frac{x-1}{x-3}$ - $\frac{2x}{x+3}$ = $\frac{2x-33}{x^{2}-9}$
4, $\frac{5x}{x+1}$ - $\frac{3}{x-1}$ = $\frac{5(x^{2}+1)}{x^{2}-1}$
5, $\frac{5}{x+2}$ - $\frac{x}{4-x^{2}}$ = $\frac{2}{x-2}$
6, $\frac{1}{x-3}$ - $\frac{4}{x+3}$ = $\frac{3x}{9-x^{2}}$
7, $\frac{4}{2x-3}$ - $\frac{4x}{4x^{2}-9}$ = $\frac{1}{2x-3}$
8, $\frac{x-1}{x-3}$ - $\frac{2x}{x+3}$ = $\frac{2x-3}{x^{2}-9}$
9, $\frac{x+3}{x-3}$ - $\frac{x-3}{x+3}$ = $\frac{36}{x^{2}-9}$
10, $\frac{x-3}{x-2}$ - $\frac{3x}{x+2}$ = $\frac{-6}{x^{2}-4}$
Giúp mk nha !!!
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Sinh Học lớp 12
