Đáp án:
p) 1
Giải thích các bước giải:
\(\begin{array}{l}
a)\dfrac{7}{6}.\dfrac{6}{7} + {\left( { - \dfrac{3}{2}} \right)^5}.{\left( { - \dfrac{2}{3}} \right)^3}\\
= 1 + {\left( {\dfrac{3}{2}} \right)^2} = 1 + \dfrac{9}{4} = \dfrac{{13}}{4}\\
c)\dfrac{{{5^4}{{.2}^4}{{.3}^{2.4}}}}{{{5^3}{{.3}^{2.5}}{{.2}^4}}} = \dfrac{{{{5.3}^8}}}{{{3^{10}}}} = \dfrac{5}{{{3^2}}} = \dfrac{5}{9}\\
e)\dfrac{9}{{16}} + \dfrac{{11}}{{18}} - \dfrac{5}{{12}}.12 = \dfrac{{169}}{{144}} - 5 = - \dfrac{{551}}{{144}}\\
k)\dfrac{4}{{13}}\left( { - \dfrac{5}{{17}} - \dfrac{{12}}{{17}} + 1} \right)\\
= \dfrac{4}{{13}}.\left( { - 1 + 1} \right) = 0\\
p){5^{2.10}}.\dfrac{1}{{{5^{20}}}} + {\left( { - \dfrac{3}{4}.\left( { - \dfrac{4}{3}} \right)} \right)^8} - 1\\
= 1 + 1 - 1 = 1
\end{array}\)
