Đáp án:
4. nZn=52/65=0.8(mol)
Zn+2HCl->ZnCl2+H2 (1)
(1)=>nH2=nZn=0.8(mol)
2H2+O2->2H2O (2)
(2)=>nO2=1/2nH2=0.4(mol)
2KClO3->2KCl+3O2 (3)
(3)=>nKClO3=2/3nO2=2/3*0.4=0.27(mol)
=>mKClO3=0.27*122.5=32.66(gam)
5. 2Al+3H2SO4->Al2(SO4)3+3H2
a. nH2SO4=29.4/98=0.3(mol)
nAl=2/3nH2SO4=2/3*0.3=0.2(mol)
nH2=nH2SO4=0.3(mol)
=>nAl=0.2*27=5.4(gam)
=>vH2=0.3*22.4=6.72(lít)
b. 4Al+3O2->2Al2O3
nO2=3/4nAl=3/4*0.2=0.15(mol)
VO2=0.15*22.4=3.36(lít)
c. 2KMnO4->K2MnO4+MnO2+O2
nK2MnO4=2nO2=0.15*2=0.3(mol)
=>mK2MnO4=0.3*158=47.4(gam)
d. Fe2O3+3H2->2Fe+3H2O
nFe2O3=1.6/160=0.01(mol)
nFe=2nFe2O3=0.01*2=0.02(mol)
=>mFe=0.02*56=1.12(lít)
Giải thích các bước giải: