Giải thích các bước giải:
`text{VT}=(2ax+1)(3ax-2)-(ax-2)(6ax+1)`
`=6a^2x^2-4ax+3ax-2-(6a^2x^2+ax-12ax-2)`
`=6a^2x^2-ax-2-(6a^2x^2-11ax-2)`
`=6a^2x^2-ax-2-6a^2x^2+11ax+2`
`=(6a^2x^2-6a^2x^2)+(11ax-ax)+(2-2)`
`=10ax=text{VP}`
Vậy `(2ax+1)(3ax-2)-(ax-2)(6ax+1)=10ax`