a,$ZnO+H_2SO_4→ZnSO_4+H_2O$
b,$n_{ZnO}=16,2/81=0,2(mol)$
$⇒n_{H_2SO_4}=0,2(mol)$
$⇒m_{H_2SO_4}=0,2.98=19,6(g)$
$⇒m_{ddH_2SO_4}=19,6.100/9,8=200(g)$
c,$n_{ZnSO_4}=0,2(mol)$
$⇒m_{ZnSO_4}=0,2.161=32,2(g)$
$m_{ddspu}=m_{ZnO}+m_{ddH_2SO_4}=16,2+200=216,2(g)$
$⇒$%$ZnSO_4=32,2.100/216,2≈14,9$%