Đáp án:
1/ x+$\frac{3}{4}$ = $\frac{-2}{3}$
⇔x=$\frac{-17}{12}$
2/ $\frac{1}{4}$ - x = $\frac{-5}{6}$
⇔x = $\frac{13}{12}$
3/ x - $\frac{5}{6}$ = $\frac{1}{-4}$
⇔x = $\frac{7}{12}$
4/ $\frac{-6}{5}$ - x = $\frac{2}{9}$ - $\frac{-4}{9}$
⇔$\frac{-6}{5}$ - x = $\frac{2}{3}$
⇔x = $\frac{-28}{15}$
5/ x - $\frac{1}{2}$ = $\frac{1}{4}$ - $\frac{1}{3}$
⇔x - $\frac{1}{2}$ = $\frac{-1}{12}$
⇔x = $\frac{5}{12}$
6/ $\frac{x}{2}$ - $\frac{2}{5}$ = $\frac{1}{10}$
⇔$\frac{x}{2}$ = $\frac{1}{2}$
⇔x = 1
7/ $\frac{15}{x}$ - $\frac{1}{3}$ = $\frac{28}{51}$
⇔$\frac{15}{x}$ = $\frac{15}{17}$
⇔x = 17
8/ ( -x + $\frac{3}{5}$ ) + $\frac{13}{20}$ = $\frac{5}{6}$
⇔-x + $\frac{3}{5}$ = $\frac{11}{60}$
⇔-x = $\frac{-5}{12}$
⇔x = $\frac{5}{12}$
9/ |x| - $\frac{7}{6}$ = $\frac{4}{15}$
⇔|x| = $\frac{43}{30}$
⇔\(\left[ \begin{array}{l}x=\frac{43}{30} \\x=\frac{-43}{30} \end{array} \right.\)
10/ $\frac{5}{6}$ - |x| = $\frac{7}{12}$ - $\frac{1}{3}$
⇔$\frac{5}{6}$ - |x| = $\frac{1}{4}$
⇔|x| = $\frac{7}{12}$
⇔\(\left[ \begin{array}{l}x=\frac{7}{12} \\x=\frac{-7}{12} \end{array} \right.\)
Nhớ cho 5 sao nhé, mik làm hơi lâu
