Em tham khảo nha :
\(\begin{array}{l}
CTHH:{M_x}{O_y}\\
x + y = 5\\
{M_A} = 4{M_{MgO}} = 4 \times 40 = 160dvC\\
\% O = \dfrac{{y{M_O}}}{{x{M_M} + y{M_O}}} \times 100\% = 30\% \\
\Rightarrow \dfrac{{16y}}{{x{M_M} + 16y}} = 0,3\\
x = 2;y = 3 \Rightarrow {M_M} = \dfrac{{16 \times 3 - 16 \times 3 \times 0,3}}{{0,3 \times 2}} = 56dvC\\
\Rightarrow M:\text{Sắt}(Fe)
\end{array}\)