Em tham khảo nha :
\(\begin{array}{l}
MgO + {H_2}S{O_4} \to MgS{O_4} + {H_2}O\\
CuO + {H_2}S{O_4} \to CuS{O_4} + {H_2}O\\
{n_{{H_2}S{O_4}}} = 0,125 \times 1 = 0,125mol\\
{n_{{H_2}O}} = {n_{{H_2}S{O_4}}} = 0,125mol\\
{n_O} = {n_{{H_2}O}} = 0,125mol\\
MgO + 2HCl \to MgC{l_2} + {H_2}O\\
CuO + 2HCl \to CuC{l_2} + {H_2}O\\
{n_{HCl}} = 2{n_O} = 0,25mol\\
{m_{HCl}} = 0,25 \times 36,5 = 9,125g\\
{m_{ddHCl}} = \dfrac{{9,125 \times 100}}{{14,6}} = 62,5g
\end{array}\)