Đáp án:
$\begin{array}{l}
c){\left( {4x - 3} \right)^2} - \left( {2x + 5} \right)\left( {2x - 5} \right)\\
= 16{x^2} - 24x + 9 - \left( {4{x^2} - 25} \right)\\
= 12{x^2} - 24x + 34\\
d){\left( {2x - 4} \right)^3} - 3{x^2}\left( {2{x^2} + 3x - 6} \right)\\
= 8{x^3} - 3.4{x^2}.4 + 3.2x.16 - 64\\
- 6{x^4} - 9{x^3} + 18{x^2}\\
= - 6{x^4} - {x^3} - 30{x^2} + 96x - 64\\
e){\left( {2x + 1} \right)^3} - \left( {3x + 2} \right)\left( {9{x^2} - 6x + 4} \right)\\
= 8{x^3} + 12{x^2} + 6x + 1\\
- \left( {27{x^3} + 8} \right)\\
= - 19{x^3} + 12{x^2} + 6x - 7
\end{array}$