\(\begin{array}{|c|c|c|}\hline
\text{Hàm số}&\text{Đạo hàm}&\matrix{\text{Khoảng}\\\text{đồng biến}}&\matrix{\text{Khoảng}\\\text{nghịch biến}}\\\hline
y = \dfrac{x-2}{x+1}&y' = \dfrac{3}{(x+1)^2}&\matrix{(-\infty;-1)\\(-1;+\infty)}&\\\hline
y = \dfrac{x-1}{x-3}&y' = -\dfrac{2}{(x-3)^2}&&\matrix{(-\infty;3)\\(3;+\infty)}\\\hline
y = \dfrac{x}{2x+1}&y' = \dfrac{1}{(2x+1)^2}&\matrix{\left(-\infty;-\dfrac12\right)\\\left(-\dfrac12;+\infty\right)}&\\\hline
y = \dfrac{4-x}{x+3}&y' = -\dfrac{7}{(x+3)^2}&&\matrix{(-\infty;-3)\\(-3;+\infty)}\\\hline
\end{array}\)