Giải thích các bước giải:
`(5+x)^2-(2x-3)^2=0`
`=>(x+5)^2=(2x-3)^2`
`=>`\(\left[ \begin{array}{l}x+5=2x-3\\x+5=3-2x\end{array} \right.\) `=>`\(\left[ \begin{array}{l}2x-x=5+3\\x+2x=3-5\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}x=8\\3x=-2\end{array} \right.\) `=>`\(\left[ \begin{array}{l}x=8\\x=-\dfrac23\end{array} \right.\)
Vậy `x in {8;-2/3}.`