Đáp án:
Giải thích các bước giải:
\[\begin{array}{l}
CdC{O_3} \to C{d^{2 + }} + C{O_3}^{2 - }\,\,\,\,\,{T_{CdC{O_3}}} = 2,{5.10^{ - 14}}\\
\,\,\,S\,\,\,\,\,\,\, \to \,\,\,\,\,\,\,\,S\,\,\,\,\,\, \to \,\,\,\,\,S\\
T = {\rm{[C}}{{\rm{d}}^{2 + }}{\rm{]}}.{\rm{[}}C{O_3}^{2 - }{\rm{]}} = {S^2} \Rightarrow S = \sqrt T = \sqrt {2,{{5.10}^{ - 14}}} = 1,{58.10^{ - 7}}
\end{array}\]