Đáp án:
\(\begin{array}{l}
{I_1} = \dfrac{5}{{22}}A\\
{I_2} = \dfrac{5}{{88}}A
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
{R_1} = \dfrac{{U_{dm1}^2}}{{{P_{dm1}}}} = \dfrac{{{{220}^2}}}{{100}} = 484\Omega \\
{R_2} = \dfrac{{U_{dm2}^2}}{{{P_{dm2}}}} = \dfrac{{{{220}^2}}}{{251}} = 1936\Omega \\
{I_1} = \dfrac{U}{{{R_1}}} = \dfrac{{110}}{{484}} = \dfrac{5}{{22}}A\\
{I_2} = \dfrac{U}{{{R_2}}} = \dfrac{{110}}{{1936}} = \dfrac{5}{{88}}A
\end{array}\)