$3x^{2}$ - $\sqrt[]{24}x$ = $22^{}$
⇒$x(3-\sqrt[]{24})^{}$ = $22^{}$
⇒$x(3-2\sqrt[]{6})^{}$ = $22^{}$
⇒$x^{}$ = $\dfrac{22}{3-2\sqrt[]{6}}$
⇒$x^{}$ = \(\left[ \begin{array}{l}\dfrac{\sqrt[]{6}-6\sqrt[]{3}}{3}\\\dfrac{\sqrt[]{6}+6\sqrt[]{3}}{3}\end{array} \right.\)