Gọi nMg = a = nFe.
Fe -> Fe+3 + 3e
a 3a
Mg -> Mg+2 + 2e
a 2a
Mn+7 + 5e -> Mn+2
0.1 0.5
bảo toàn e => 3a + 2a = 0.5
=> a = 0.1 mol
23,975 = mFe + mFe + mCl2
=> m Cl2 = 15.975g
-> nCl2 = 0.225 l
=> V Cl2 = 5.04 l
m = mMg + mFe = 0.1 x 24 + 0.1 x 56 = 8g