Bài $5$
$\dfrac{-19}{6}+\dfrac{-15}{2}+\dfrac{11}{3}<x≤\dfrac{-5}{4}+\dfrac{19}{2}+\dfrac{-10}{3}$
$⇒\dfrac{-19}{6}+\dfrac{-45}{6}+\dfrac{22}{6}<x≤\dfrac{-15}{12}+\dfrac{114}{12}+\dfrac{-40}{12}$
$⇒\dfrac{-19-45+22}{6}<x≤\dfrac{-15+114-40}{12}$
$⇒\dfrac{-42}{6}<x≤\dfrac{59}{12}$
$⇒-7<x≤4,9...<5$
$⇒-7<x<5$
$⇒x∈\{0;±1;±2;±3;±4;-5;-6\}$
Bài $6$
$a,\dfrac{1}{4}=\dfrac{3}{12}=\dfrac{1}{12}+\dfrac{2}{12}=\dfrac{1}{12}+\dfrac{1}{6}$
$b,\dfrac{7}{150}=\dfrac{2}{150}+\dfrac{5}{150}=\dfrac{1}{75}+\dfrac{1}{30}$
