Đáp án:
Giải thích các bước giải:
Bài 1:
a,$3^{6}$:$3^{3}$=$3^{3}$
b,$5^{2012}$:$5^{2012}$=$5^{0}$=$1^{}$
c,$25^{4}$:$5^{2}$=$5^{8}$:$5^{2}$=$5^{6}$
Bài 2:
$2^{2}$.$16^{}$:$2^{3}$=$4^{}$.$16:8^{}$=$8^{}$
Bài 3
a,$3^{5}$.$9^{}:$$243^{}$=$3^{7}$:$3^{5}$=$3^{2}$
b,$2^{4}$:$2^{}$.$8^{}$=$16:16^{}$=$1^{}$
c,$25^{3}$.$25^{2}$:$125^{}$.$5^{2}$=$25^{5}$:$5^{5}$=$5^{5}$
Bài 4:
a,$42.57^{}$+$43.42^{}$-$600^{}$=$42^{}$.$(57+43)^{}$-$600^{}$=$42^{}$.$100^{}$-$600^{}$=$3600^{}$
b,$2^{2}$.$5^{2}$-$64^{}$:$2^{3}$=$10^{2}$$-8^{}$=$100-8^{}$=$92^{2}$
Bài 5:
a,$91-5(5+x)=6^{}$
$5(5+x)=30^{}$
$(5+x)=30:5=6^{}$
$x=6-5=1^{}$
$ Vậy x=1^{}$
b,$[(x+34)-50].2=56^{}$
$[(x+34)-50]=28^{}$
$x+34=78^{}$
$x=78-34=44^{}$
Vậy $x=44^{}$
