Đáp án:
Giải thích các bước giải:
$1. x^2-6x+9=(x-3)^2$
$2. 25+10x+x^2=(5+x)^2$
$3. \frac{1}{4}a^2+2ab^2+4b^4=(\frac{1}{2}+2b)^2$
$4. \frac{1}{9}-\frac{2}{3}y^4+y^8=(\frac{1}{3}-y^4)^2$
$5. x^3+8y^3=(x+2y)(x^2-2xy+4y^2)$
$6. 8y^3-125=(2y-5)(4y^2+10y+25)$
$7. a^6-b^3=(a^3-b)(a^6+2a^3b+b^2)$
$8.x^2-10x+25=(x-5)^2$
$9. 8x^3-\frac{1}{8}=(2x-\frac{1}{2})(4x^2+x+\frac{1}{4})$
$10. x^2+4xy+4y^2=(x+2y)^2$
$8.(3x+2)^2-4=(3x+2-2)(3x+2+2)=3x(3x+4)$
$9.4x^2-25y^2=(2x-5y)(2x+5y)$
$10.4x^2-49=(2x-7)(2x+7)$
$11.8z^3+27=(2z+3)(4z^2-6z+9)$
$12. \frac{9}{25}x^4-\frac{1}{4}=(\frac{3}{5}x^2-\frac{1}{2})(\frac{3}{5}x^2+\frac{1}{2})$
$13.x^32-1$
$=(x^16-1)(x^16+1)$
$=(x^8-1)(x^8+1)(x^16+1)$
$=(x^4-1)(x^4+1)(x^8+1)(x^16+1)$
$=(x^2-1)(x^2+1)(x^4+1)(x^8+1)(x^16+1)$
$=(x-1)(x+1)(x^2+1)(x^4+1)(x^8+1)(x^16+1)$
$14. 4x^2+4x+1=(2x+1)^2$
$15. x^2-20x+100=(x-10)^2$
$16. y^4-14y^2+49=(y^2-7)^2$
$17. 125x^3-64y^3=(5x-4y)(25x^2+20xy+16y^2)$
Chúc bạn học tốt . Mình xin câu trả lời hay nhất nhé
