Đáp án:
Bài 2
a, 3x+25%. $\frac{4}{5}$ =-1$\frac{1}{2}$
3x+$\frac{1}{5}$ =$\frac{-3}{2}$
3x =$\frac{-3}{2}$ - $\frac{1}{5}$
3x =$\frac{-17}{10}$ :3
x =$\frac{-17}{30}$
b,2.║$\frac{1}{2}$x-$\frac{1}{3}$ ║-$\frac{3}{2}$ =$\frac{1}{4}$
2.║$\frac{1}{2}$x-$\frac{1}{3}$ ║ =$\frac{1}{4}$ +$\frac{3}{2}$
2.║$\frac{1}{2}$x-$\frac{1}{3}$ ║ =$\frac{7}{4}$
║$\frac{1}{2}$x-$\frac{1}{3}$ ║ =$\frac{7}{4}$ :2
║$\frac{1}{2}$x-$\frac{1}{3}$ ║ =$\frac{7}{8}$
$\frac{1}{2}$x-$\frac{1}{3}$= $\frac{7}{8}$ hoặc $\frac{1}{2}$x-$\frac{1}{3}$ =$\frac{-7}{8}$
$\frac{1}{2}$x =$\frac{7}{8}$+$\frac{1}{3}$
$\frac{1}{2}$x =$\frac{29}{24}$
x =$\frac{29}{24}$: $\frac{1}{2}$
x =$\frac{29}{12}$
hoặc $\frac{1}{2}$x-$\frac{1}{3}$ =$\frac{-7}{8}$
$\frac{1}{2}$x =$\frac{-7}{8}$+$\frac{1}{3}$
$\frac{1}{2}$x =$\frac{-13}{24}$
x =$\frac{-13}{24}$: $\frac{1}{2}$
x =$\frac{-13}{12}$
@tuanbach1104
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