Câu 2
$C_{n}$$H_{2n+1}OH$ + $Na_{}$ → $C_{n}$$H_{2n+1}ONa$ + $\frac{1}{2}$$H_{2}$
0,04 ← $\frac{0,448}{22,4}$
⇒ 14n + 18 = $\frac{2,4}{0,04}$
→ n = 3
a. CTPT(A): $C_{3}$$H_{7}OH$
b. CTCT(A): + $CH_{3}-$$CH_{2}-$$CH_{2}-OH$
Ancol Propylic / Propan - 1 ol
+ $CH_{3}-$$CH_{}-$$(CH_{3})OH$
Ancol isopropylic / Propan - 2 - ol