Giải thích các bước giải:
3/
$m_{S}$ =NTK(S) x 1đvC = 32 . 1,6605 . $10^{-24}$ = 53,136 . $10^{-24}$ (g)
$m_{Al}$ = NTK(Al) x 1đvC = 27 . 1,6605 . $10^{-24}$ = 44,8335 . $10^{-24}$ (g)
$m_{Ca}$ = NTK(Ca) x 1đvC = 40 . 1,6605 . $10^{-24}$ = 66,42 . $10^{-24}$
$m_{Na}$ = NTK(Na) x 1đvC = 23 . 1,6605 . $10^{-24}$ = 38,1915 . $10^{-24}$
$m_{N}$ = NTK(N) x 1đvC = 14 . 1,6605 . $10^{-24}$ = 23,247 . $10^{-24}$
$m_{Cu}$ = NTK(Cu) x 1đvC = 64 . 1,6605 . $10^{-24}$ = 106,272 . $10^{-24}$
$m_{Fe}$ = NTK(Fe) x 1đvC = 56 . 1,6605 . $10^{-24}$ = 92,988 . $10^{-24}$
4/
NTK(A) = $\frac{5,312 . 10^{-23} }{1,6605 . 10^{-24} }$ = 32
⇒ A là ngtử lưu huỳnh và (KHHH) A : S