Nếu đề bài là tìm nghiệm
$x:(\dfrac{1}{2}+\dfrac{1}{3})+\dfrac{6}{5}=0$
$x:\dfrac{5}{6}=-\dfrac{6}{5}$
$x=-\dfrac{6}{5}.\dfrac{5}{6}=-1$
Nếu đề là: $x:(\dfrac{1}{2}+\dfrac{1}{3})=\dfrac{6}{5}$
$x:\dfrac{5}{6}=\dfrac{6}{5}$
$x=\dfrac{6}{5}.\dfrac{5}{6}=1$