Đáp án:
\( m_{{H_2}S{O_4}.3S{O_3}} = 60,01528{\text{ gam}}\)
Giải thích các bước giải:
Gọi số mol \(H_2SO_3.3SO_3\) là \(x\)
Phản ứng xảy ra:
\({H_2}S{O_4}.3S{O_3} + 3{H_2}O\xrightarrow{{}}4{H_2}S{O_4}\)
\({n_{{H_2}S{O_4}}} = 4{n_{{H_2}S{O_4}.3{H_2}O}} = 4x{\text{ mol}}\)
\( \to {m_{{H_2}S{O_4}}} = 4x.98 = 392x{\text{ gam}}\)
\({m_{dd}} = {m_{{H_2}S{O_4}.3S{O_3}}} + {m_{{H_2}O}} = 338x + 288{\text{ gam}}\)
\( \to 392x = 20\% (338x + 288) \to x = 0,17756{\text{ mol}}\)
\( \to {m_{{H_2}S{O_4}.3S{O_3}}} = 338x = 60,01528{\text{ gam}}\)
