Giải thích các bước giải:
\(\begin{array}{l}
1.\\
a)CuO + 2HCl \to CuC{l_2} + {H_2}O\\
b)\\
{m_{HCl}} = \dfrac{{200 \times 7,3\% }}{{100\% }} = 14,6g\\
\to {n_{HCl}} = 0,4mol\\
\to {n_{CuO}} = {n_{CuC{l_2}}} = \dfrac{1}{2}{n_{HCl}} = 0,2mol\\
\to {m_{CuO}} = 16g\\
\to {m_{CuC{l_2}}} = 27g\\
2.\\
a)CuO + 2HCl \to CuC{l_2} + {H_2}O\\
b)\\
{n_{HCl}} = 0,2mol\\
\to {n_{CuO}} = \dfrac{1}{2}{n_{HCl}} = 0,1mol\\
\to {m_{CuO}} = 8g\\
c)\\
{n_{CuC{l_2}}} = \dfrac{1}{2}{n_{HCl}} = 0,1mol\\
\to C{M_{CuC{l_2}}} = \dfrac{{0,1}}{{0,2}} = 0,5M
\end{array}\)