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Bạn tham khảo bài.
Câu `1.`
`x=1/(2013.2012)-1/(2012.2011)-...-1/(3.2)-1/(2.1)`
`->x=1/(2013.2012)-(1/(1.2)+1/(2.3)+...+1/(2011.2012))`
`->x=1/(2013.2012)-(1-1/2+1/2-1/3+...+1/2011-1/2012)`
`->x=1/(2013.2012)-(1 - 1/2012)`
`->x = 1/(2013 . 2012) - 2011/2012`
`->x=1/(2013.2012)-(2013.2011)/(2013.2012)`
`->x=(1 - 2013.2011)/(2013.2012)`
Vậy `x=(1 - 2013.2011)/(2013.2012)`
Câu `2.`
`x-20/(11.13)-... - 20/(53.55)=(-3)/11`
`->x-(20/(11.13)+...+20/(53.55))=(-3)/11`
`->x-20 (1/(11.13)+...+1/(53.55))=(-3)/11`
`->x - 20 . 1/2 . (1/11-1/13+...+1/53-1/55)=(-3)/11`
`->x - 10 . (1/11-1/55)=(-3)/11`
`->x-10 . 4/55=(-3)/11`
`->x-8/11=(-3)/11`
`->x=5/11`
Vậy `x=5/11`